To split on whitespace, see How do I split a string into a list of words?. To extract everything before the first delimiter, see Splitting on first occurrence. To extract everything before the last …

return re.split(regex_pattern, string, maxsplit) If you're going to split often using the same delimiters, compile your regular expression beforehand like described and use …

If you want to split by 1 or more occurrences of a delimiter and don't want to just count on the default split() with no parameters happening to match your use case, you can use regex to …

I would like to split a string, with multiple delimiters, but keep the delimiters in the resulting list. I think this is a useful thing to do an an initial step of parsing any kind of formula, and I suspect …

9 Here is a simple .split solution that works without regex. This is an answer for Python split () without removing the delimiter, so not exactly what the original post asks but the other …

If df['V'].str.split('-') returns a list, why do we need to use a string accessor in order to index the list components? My assumption was df['V'].str.split('-')[0] would be all that is needed.

Well thanks anyway, user. To be fair though I specifically asked for split and then strip () and strip removes leading and trailing whitespace and doesn't touch anything in between. A slight …

Both methods start splitting from the right-hand-side of the string; by giving str.rsplit() a maximum as the second argument, you get to split just the right-hand-most occurrences.

Using split() will be the most Pythonic way of splitting on a string. It's also useful to remember that if you use split() on a string that does not have a whitespace then that string will be returned to …

What would be the best way to split a string on the first occurrence of a delimiter? For example: "123mango abcd mango kiwi peach" splitting on the first mango to get: " abcd …