In python, as far as I know, there are at least 3 to 4 ways to create and initialize lists of a given size: Simple loop with append: my_list = [] for i in range(50): my_list.append(0) Simple ...

4149 new_list = my_list doesn't actually create a second list. The assignment just copies the reference to the list, not the actual list, so both new_list and my_list refer to the same list after the assignment. …

Same comment here, this doesn't solve the more general problem of "Pythonic way to return list of every n’th item in a larger list" your solution depends on the fact that the example list's values are 0 to 1000 …

Oct 26, 2015 · My exemplary list contains integers from 1 to 6 and I want to retrieve 4 items from this list. I used the %timeit functionality of Jupyter Notebook / iPython on a Windows 10 system with Python …

Jun 12, 2019 · 1 I am trying to make a new list, which is a replica of an other list. This new list I want to modify by changing values at specific positions. I found this question, and the most upvoted answer …

8 I have a list below. I need to use it to create a new list with only country names. How do I loop x in order to have a list of country names?

Mar 9, 2017 · The pythonic way of removing an element while copying is using comprehension lists: [x for x in my_list if x != element]. So there is no need of a function for this.

@Hugo, to see the list of duplicates, we just need to create a new list called dup and add an else statement. For example: dup = [] else: dup.append(x)

It will append it to the original list,now you can return the variable containing the original list. If you are working with very large lists this is the way to go.

Jul 11, 2011 · Yes, creating a list of lists is indeed the easiest and best solution. I do favor teaching new Python users about list comprehensions, since they exhibit a clean, expression-oriented style that is …